The Monster is the largest of the 26 sporadic simple groups and has order
808 017 424 794 512 875 886 459 904 961 710 757 005 754 368 000 000 000
= 2^46 3^20 5^9 7^6 11^2 13^3 17 19 23 29 31 41 47 59 71.
It is not so much the size of its order that makes it hard to do actual calculations in the monster, but rather the dimensions of its smallest non-trivial irreducible representations (196 883 for the smallest, 21 296 876 for the next one, and so on).
In characteristic two there is an irreducible representation of one dimension less (196 882) which appears to be of great use to obtain information. For example, Robert Wilson used it to prove that The Monster is a Hurwitz group. This means that the Monster is generated by two elements g and h satisfying the relations

Geometrically, this implies that the Monster is the automorphism group of a Riemann surface of genus g satisfying the Hurwitz bound 84(g-1)=#Monster. That is,
g=9619255057077534236743570297163223297687552000000001=42151199 * 293998543 * 776222682603828537142813968452830193
Or, in analogy with the Klein quartic which can be constructed from 24 heptagons in the tiling of the hyperbolic plane, there is a finite region of the hyperbolic plane, tiled with heptagons, from which we can construct this monster curve by gluing the boundary is a specific way so that we get a Riemann surface with exactly 9619255057077534236743570297163223297687552000000001 holes. This finite part of the hyperbolic tiling (consisting of #Monster/7 heptagons) we’ll call the empire of the monster and we’d love to describe it in more detail.
Look at the half-edges of all the heptagons in the empire (the picture above learns that every edge in cut in two by a blue geodesic). They are exactly #Monster such half-edges and they form a dessin d’enfant for the monster-curve.
If we label these half-edges by the elements of the Monster, then multiplication by g in the monster interchanges the two half-edges making up a heptagonal edge in the empire and multiplication by h in the monster takes a half-edge to the one encountered first by going counter-clockwise in the vertex of the heptagonal tiling. Because g and h generated the Monster, the dessin of the empire is just a concrete realization of the monster.
Because g is of order two and h is of order three, the two permutations they determine on the dessin, gives a group epimorphism
from the
modular group
onto the Monster-group.
In noncommutative geometry, the group-algebra of the modular group
can be interpreted as the coordinate ring of a noncommutative manifold (because it is formally smooth in the sense of
Kontsevich-Rosenberg or Cuntz-Quillen) and the group-algebra of the Monster
itself corresponds in this picture to a finite collection of ‘points’ on the manifold. Using this geometric viewpoint we can now ask the question What does the Monster see of the modular group?
To make sense of this question, let us first consider the commutative equivalent : what does a point P see of a commutative variety X?
Evaluation of polynomial functions in P gives us an algebra epimorphism
from the coordinate ring of the variety
onto
and the kernel of this map is the maximal ideal
of
consisting of all functions vanishing in P.
Equivalently, we can view the point
as the scheme corresponding to the quotient
. Call this the 0-th formal neighborhood of the point P.
This sounds pretty useless, but let us now consider higher-order formal neighborhoods. Call the affine scheme
the n-th forml neighborhood of P, then the first neighborhood, that is with coordinate ring
gives us tangent-information. Alternatively, it gives the best linear approximation of functions near P.
The second neighborhood
gives us the best quadratic approximation of function near P, etc. etc.
These successive quotients by powers of the maximal ideal
form a system of algebra epimorphisms
![\hdots \frac{\mathbb{C}[X]}{\mathfrak{m}_P^{n+1}} \rightarrow \frac{\mathbb{C}[X]}{\mathfrak{m}_P^{n}} \rightarrow \hdots \hdots \rightarrow \frac{\mathbb{C}[X]}{\mathfrak{m}_P^{2}} \rightarrow \frac{\mathbb{C}[X]}{\mathfrak{m}_P} = \mathbb{C} \hdots \frac{\mathbb{C}[X]}{\mathfrak{m}_P^{n+1}} \rightarrow \frac{\mathbb{C}[X]}{\mathfrak{m}_P^{n}} \rightarrow \hdots \hdots \rightarrow \frac{\mathbb{C}[X]}{\mathfrak{m}_P^{2}} \rightarrow \frac{\mathbb{C}[X]}{\mathfrak{m}_P} = \mathbb{C}](/latexrender/pictures/5199d43b19162aa2866b764448eb9007.gif)
and its inverse limit
is the completion of the local ring in P and contains all the infinitesimal information (to any order) of the variety X in a neighborhood of P. That is, this completion
contains all information that P can see of the variety X.
In case P is a smooth point of X, then X is a manifold in a neighborhood of P and then this completion
is isomorphic to the algebra of formal power series
where the
form a local system of coordinates for the manifold X near P.
Right, after this lengthy recollection, back to our question what does the monster see of the modular group? Well, we have an algebra epimorphism

and in analogy with the commutative case, all information the Monster can gain from the modular group is contained in the
-adic completion

where
is the kernel of the epimorphism
sending the two free generators of the modular group
to the permutations g and h determined by the dessin of the pentagonal tiling of the Monster’s empire.
As it is a hopeless task to determine the Monster-empire explicitly, it seems even more hopeless to determine the kernel
let alone the completed algebra… But, (surprise) we can compute
as explicitly as in the commutative case we have
for a point P on a manifold X.
Here the details : the quotient
has a natural structure of
-bimodule. The group-algebra of the monster is a semi-simple algebra, that is, a direct sum of full matrix-algebras of sizes corresponding to the dimensions of the irreducible monster-representations. That is,

with exactly 194 components (the number of irreducible Monster-representations). For any
-bimodule
one can form the tensor-algebra

and applying the formal neighborhood theorem for formally smooth algebras (such as
) due to
Joachim Cuntz (left) and
Daniel Quillen (right) we have an isomorphism of algebras

where the right-hand side is the completion of the tensor-algebra (at the unique graded maximal ideal) of the
-bimodule
, so we’d better describe this bimodule explicitly.
Okay, so what’s a bimodule over a semisimple algebra of the form
? Well, a simple S-bimodule must be either (1) a factor
with all other factors acting trivially or (2) the full space of rectangular matrices
with the factor
acting on the left,
acting on the right and all other factors acting trivially.
That is, any S-bimodule can be represented by a quiver (that is a directed graph) on k vertices (the number of matrix components) with a loop in vertex i corresponding to each simple factor of type (1) and a directed arrow from i to j corresponding to every simple factor of type (2).
That is, for the Monster, the bimodule
is represented by a quiver on 194 vertices and now we only have to determine how many loops and arrows there are at or between vertices.
Using Morita equivalences and standard representation theory of quivers it isn’t exactly rocket science to determine that the number of arrows between the vertices corresponding to the irreducible Monster-representations
and
is equal to

Now, I’ve been wasting a lot of time already here explaining what representations of the modular group have to do with quivers (see for example here or some other posts in the same series) and for quiver-representations we all know how to compute Ext-dimensions in terms of the Euler-form applied to the dimension vectors.
Right, so for every Monster-irreducible
we have to determine the corresponding dimension-vector
for the quiver
![\xymatrix{ & & & &
\vtx{b_1} \\ \vtx{a_1} \ar[rrrru]^(.3){B_{11}} \ar[rrrrd]^(.3){B_{21}}
\ar[rrrrddd]_(.2){B_{31}} & & & & \\ & & & & \vtx{b_2} \\ \vtx{a_2}
\ar[rrrruuu]_(.7){B_{12}} \ar[rrrru]_(.7){B_{22}}
\ar[rrrrd]_(.7){B_{23}} & & & & \\ & & & & \vtx{b_3}} \xymatrix{ & & & &
\vtx{b_1} \\ \vtx{a_1} \ar[rrrru]^(.3){B_{11}} \ar[rrrrd]^(.3){B_{21}}
\ar[rrrrddd]_(.2){B_{31}} & & & & \\ & & & & \vtx{b_2} \\ \vtx{a_2}
\ar[rrrruuu]_(.7){B_{12}} \ar[rrrru]_(.7){B_{22}}
\ar[rrrrd]_(.7){B_{23}} & & & & \\ & & & & \vtx{b_3}}](/latexrender/pictures/1ca7d900d808eeda597faa97a6cf069f.gif)
Now the dimensions
are the dimensions of the +/-1 eigenspaces for the order 2 element g in the representation and the
are the dimensions of the eigenspaces for the order 3 element h. So, we have to determine to which conjugacy classes g and h belong, and from Wilson’s paper mentioned above these are classes 2B and 3B in standard
Atlas notation.
So, for each of the 194 irreducible Monster-representations we look up the character values at 2B and 3B (see below for the first batch of those) and these together with the dimensions determine the dimension vector
.

For example take the 196883-dimensional irreducible. Its 2B-character is 275 and the 3B-character is 53. So we are looking for a dimension vector such that
and
giving us for that representation the dimension vector of the quiver above
.
Okay, so for each of the 194 irreducibles
we have determined a dimension vector
, then standard quiver-representation theory asserts that the number of loops in the vertex corresponding to
is equal to

and that the number of arrows from vertex
to vertex
is equal to

This data then determines completely the
-bimodule
and hence the structure of the completion
containing all information the Monster can gain from the modular group.
But then, one doesn’t have to go for the full regular representation of the Monster. Any faithful permutation representation will do, so we might as well go for the one of minimal dimension.
That one is known to correspond to the largest maximal subgroup of the Monster which is known to be a two-fold extension
of the
Baby-Monster. The corresponding permutation representation is of dimension 97239461142009186000 and decomposes into Monster-irreducibles

(in standard Atlas-ordering) and hence repeating the arguments above we get a quiver on just 9 vertices! The actual numbers of loops and arrows (I forgot to mention this, but the quivers obtained are actually symmetric) obtained were found after laborious computations mentioned in this post and the details I’ll make avalable here.
Anyone who can spot a relation between the numbers obtained and any other part of mathematics will obtain quantities of genuine (ie. non-Inbev) Belgian beer…
of an affine algebra A to be a quiver on the isoclasses of simple finite dimensional representations. When
is the coordinate ring of an affine variety, these vertices are just the points of the variety
and this set has the extra structure of being endowed with the
of a finite group
. In this case, the vertices of the tangent quiver
whereas there are just 194 characters to consider…
and any finite dimensional simple A-representation
the character
is the matrix describing the action of a on S. But, you might say, characters are then just linear functionals on the algebra A so it is natural to view A as the function algebra, right? Wrong! Traces have the nice property that
and so they vanish on all commutators
of A, so characters only carry information of the quotient space![\mathfrak{g}_A = \frac{A}{[A,A]_{vect}} \mathfrak{g}_A = \frac{A}{[A,A]_{vect}}](/latexrender/pictures/4eb5d8bdfc4d737e80569afc182a7e2e.gif)
is the vectorspace spanned by all commutators (and not the ideal…). If one is too focussed on commutative geometry one misses this essential simplification as clearly for
and therefore in this case ![\mathfrak{g}_{\C[X]} = \C[X] \mathfrak{g}_{\C[X]} = \C[X]](/latexrender/pictures/c7c00b1eb37b4ba5815bca25703e8a5a.gif)
, that is elements of the dual space
) to separate the simple representations? And, why do I (ab)use Lie-algebra notation
???
-algebra A (not necessarily commutative). We will assign to it a strange object called the tangent-quiver
of
and between any two such vertices, say
, the number of directed arrows from 
![\xymatrix{0 \ar[r] & S_w \ar[r] & V \ar[r] & S_v \ar[r] & 0} \xymatrix{0 \ar[r] & S_w \ar[r] & V \ar[r] & S_v \ar[r] & 0}](/latexrender/pictures/79295bdb9289c15e0389919ccdcfde3e.gif)
making the diagram below commutative![\xymatrix{0 \ar[r] & S_w \ar[r] \ar[d]^{id_{S_w}} & V \ar[r] \ar[d]^{\phi} & S_v \ar[r] \ar[d]^{id_{S_v}} & 0 \\\
0 \ar[r] & S_w \ar[r] & W \ar[r] & S_v \ar[r] & 0} \xymatrix{0 \ar[r] & S_w \ar[r] \ar[d]^{id_{S_w}} & V \ar[r] \ar[d]^{\phi} & S_v \ar[r] \ar[d]^{id_{S_v}} & 0 \\\
0 \ar[r] & S_w \ar[r] & W \ar[r] & S_v \ar[r] & 0}](/latexrender/pictures/db75113e87fc6b4cc9024e320164e5b7.gif)
then what is
is commutative, all its finite dimensional simple representations are one-dimensional and there is one such for every point
. Therefore, the vertices of
corresponding to a point
is just evaluating polynomials in
then there are no non-split extensions between
(a commutative semi-local algebra splits as a direct sum of locals), therefore in ![dim_{\C}~Ext^1_{\C[X]}(S_x,S_x) = dim_{\C}~T_x~X dim_{\C}~Ext^1_{\C[X]}(S_x,S_x) = dim_{\C}~T_x~X](/latexrender/pictures/1ee42834fa98fe925db931cc0ecf526f.gif)
. So, in this case, the quiver
of a finite group
of a finite quiver
without oriented cycles. Recall that the path algebra is the vectorspace having as basis all vertices and all oriented paths in the quiver Q (and as there are no cycles, this basis is finite) and multiplication is induced by concatenation of paths. Here an easy example. Suppose the quiver Q looks like![\xymatrix{\vtx{} \ar[r] & \vtx{} \ar[r] & \vtx{}} \xymatrix{\vtx{} \ar[r] & \vtx{} \ar[r] & \vtx{}}](/latexrender/pictures/e396315d4f3cf8c5deb4147af9b7699b.gif)
matrices
where
is the vertex idempotent. No doubt, you can guess what the tangent quiver
will be, can’t you?
-representations. Last time, we
have explained Grothendiecks
mantra that all algebraic curves defined over number fields are
contained in the profinite compactification
of the modular
group
correspond to permutation
representations of
is
a continuous group, so it makes sense to consider its continuous
n-dimensional representations
Such representations are known to have a finite image in
and therefore we get an embedding
into all n-dimensional
(semi-simple) representations of
-
representations of (sporadic) finite groups - modlart data of fusion
rings in RCTF - etc… To get a feel for the distinction between
these continuous representations of the cofinite completion and all
representations, consider the case of
. Its
one-dimensional continuous representations are determined by roots of
unity, whereas all one-dimensional (necessarily simple) representations
of
are determined by all elements of
is contained in the unit circle
from the
dessin d’enfant
with just one arrow in each direction
between the vertices and 96 loops in the second vertex. To the
experienced tangent space-reader this picture (and in particular that
there is a unique cycle between the two vertices) tells the remarkable
fact that there is a distinguished one-parameter family of
24-dimensional simple modular representations degenerating to the
permutation representation of the largest Mathieu-group. Phrased
differently, there is a specific noncommutative modular Riemann surface
associated to
-algebra associated to it. In fact, the algebra is AF ( a limit of
semi-simple finite dimensional algebras) so is even a formally smooth
algebra in Kontsevichian noncommutative geometry (it is remarkable how
quickly one gets used to silly terminology…). However, the Penrose
algebra is simple, so rather useless from the point of view of finite
dimensional representations… Still, Connesian noncommutative geometry
may be a recent incarnation of the medieval Tehran program (pun
intended). Thanks to
