Last time we tried to generalize the
Connes-Consani approach to commutative algebraic geometry over the field with one element
to the noncommutative world by considering covariant functors

which over
resp.
become visible by a complex (resp. integral) algebra having suitable universal properties.
However, we didn’t specify what we meant by a complex noncommutative variety (resp. an integral noncommutative scheme). In particular, we claimed that the
-’points’ associated to the functor
(here
denotes all elements of order
of
)
were precisely the modular dessins d’enfants of Grothendieck, but didn’t give details. We’ll try to do this now.
For algebras over a field we follow the definition, due to Kontsevich and Soibelman, of so called “noncommutative thin schemes”. Actually, the thinness-condition is implicit in both Soule’s-approach as that of Connes and Consani : we do not consider R-points in general, but only those of rings R which are finite and flat over our basering (or field).
So, what is a noncommutative thin scheme anyway? Well, its a covariant functor (commuting with finite projective limits)

from finite-dimensional (possibly noncommutative)
-algebras to sets. Now, the usual dual-space operator gives an anti-equivalence of categories

so a thin scheme can also be viewed as a contra-variant functor (commuting with finite direct limits)

In particular, we are interested to associated to any {tex]k[/tex]-algebra
its representation functor :

This may look strange at first sight, but
is a finite dimensional algebra and any
-dimensional representation of
is an algebra map
and we take
to be the dual coalgebra of this image.
Kontsevich and Soibelman proved that every noncommutative thin scheme
is representable by a
-coalgebra. That is, there exists a unique coalgebra
(which they call the coalgebra of ‘distributions’ of
) such that for every finite dimensional
-algebra
we have

In the case of interest to us, that is for the functor
the coalgebra of distributions is Kostant’s dual coalgebra
. This is the not the full linear dual of
but contains only those linear functionals on
which factor through a finite dimensional quotient.
So? You’ve exchanged an algebra
for some coalgebra
, but where’s the geometry in all this? Well, let’s look at the commutative case. Suppose
is the coordinate ring of a smooth affine variety
, then its dual coalgebra looks like
![\C[X]^o = \oplus_{x \in X} U(T_x(X)) \C[X]^o = \oplus_{x \in X} U(T_x(X))](/latexrender/pictures/0a8bbcf65c24a37837f0568e82f1668d.gif)
the direct sum of all universal (co)algebras of tangent spaces at points
. But how do we get the variety out of this? Well, any coalgebra has a coradical (being the sun of all simple subcoalgebras) and in the case just mentioned we have
![corad(\C[X]^o) = \oplus_{x \in X} \C e_x corad(\C[X]^o) = \oplus_{x \in X} \C e_x](/latexrender/pictures/f1f529926096ef580112b00d56b1f99d.gif)
so every point corresponds to a unique simple component of the coradical. In the general case, the coradical of the dual coalgebra
is the direct sum of all simple finite dimensional representations of
. That is, the direct summands of the coalgebra give us a noncommutative variety whose points are the simple representations, and the remainder of the coalgebra of distributions accounts for infinitesimal information on these points (as do the tangent spaces in the commutative case).
In fact, it was a surprise to me that one can describe the dual coalgebra quite explicitly, and that
-structures make their appearance quite naturally. See
this paper if you’re in for the details on this.
That settles the problem of what we mean by the noncommutative variety associated to a complex algebra. But what about the integral case? In the above, we used extensively the theory of Kostant-duality which works only for algebras over fields…
Well, not quite. In the case of
(or more general, of Dedekind domains) one can repeat Kostant’s proof word for word provided one takes as the definition of the dual
-coalgebra
of an algebra (which is
-torsion free)

(over general rings there may be also variants of this duality, as in
Street’s book an Quantum groups). Probably lots of people have come up with this, but the only explicit reference I have is to the
first paper I’ve ever written. So, also for algebras over
we can define a suitable noncommutative integral scheme (the coradical approach accounts only for the maximal ideals rather than all primes, but somehow this is implicit in all approaches as we consider only thin schemes).
Fine! So, we can make sense of the noncommutative geometrical objects corresponding to the group-algebras
and
where
is the modular group (the algebras corresponding to the
-functor). But, what might be the points of the noncommutative scheme corresponding to
???
Well, let’s continue the path cut out before. “Points” should correspond to finite dimensional “simple representations”. Hence, what are the finite dimensional simple
-representations of
? (Or, for that matter, of any group
)
Here we come back to
Javier’s post on this : a finite dimensional
-vectorspace is a finite set. A
-representation on this set (of n-elements) is a group-morphism

hence it gives a permutation representation of
on this set. But then, if finite dimensional
-representations of
are the finite permutation representations, then the simple ones are the transitive permutation representations. That is, the points of the noncommutative scheme corresponding to
are the conjugacy classes of subgroups
such that
is finite. But these are exactly the modular dessins d’enfants introduced by Grothendieck as I explained a while back elsewhere (see for example
this post and others in the same series).
as in

. In a series of posts on the Connes-Consani paper (starting
together with a natural transformation (the ‘evaluation’)
may be noncommutative). The pair
is then called a gadget and there is an obvious notion of ‘morphism’ between gadgets.
such that
together with the following universal property :
having a gadget-morphism
comes from a
. (If this sounds too cryptic for you, please read the series on C-C mentioned before).
still has as its integral form the integral torus
. However, both theories quickly diverge beyond this example.
it is easy to see (again by a similar argument) that the two-dimensional integer torus
is the correct integral form. However, this algebra cannot be the correct form for the functor on the category of all finite groups as any
determines (and is determined by) a pair of commuting units in
, so the above functor can not be a subfunctor if we allow non-Abelian groups.
and
satisfying only the trivial cancellation laws between a letter and its inverse), then the corresponding integral group-algebra
does the trick.
and we have to show, using the universal property that the image of
of
is bounded say by
and we can always find a subgroup
such that
is a fnite group and the quotient map
is injective on the subspace spanned by all words of degree strictly less than
. Then, the usual diagram-chase finishes the proof.
has ‘enough’ subgroups of finite index, a property it shares with many interesting discrete groups. Whence the blurb-message :
So, yes, we get something new by extending the Connes-Consani approach to the noncommutative world, but do we have interesting examples? As “interesting” is a subjective qualification, we’d better invoke the authority-argument.
, via his theory of
-curve
ramified only in three points
. The “drawing” corresponding to
obtained by lifting the unit interval
to
, ou
est une extension de type fini du corps premier) sur des groupes fondamentaux géométriques (profinis) de variétés algébriques (définies sur
, il y a le compactifié profini du groupe modulaire
, dont le quotient par le centre
contient le précédent comme sous-groupe de congruence mod 2, et peut s’interpréter d’ailleurs comme groupe “cartographique” orienté, savoir celui qui classifie les cartes orientées triangulées (i.e. celles dont les faces des triangles ou des monogones).”
sur le compactifié profini. Par le théorème de Bielyi, prenant les compactifiés profinis de sous-groupes d’indice fini de
), on trouve essentiellement les groupes fondamentaux de toutes les courbes algébriques définis sur des corps de nombres 
.
. Using the Fun mantra that
where
having the property that every element of
-point of
there is an algebra map
.
being the forgetful functor, that is
for every finite Abelian group, then the complex algebra
partners up to form a gadget because to every element
there is a natural algebra map
defined by sending
. Clearly, there is an obvious integral form of this complex algebra, namely ![\wis{min}(\Z[x,x^{-1}])~:~\wis{abelian} \rightarrow \wis{sets} \qquad A \mapsto (\Z A)^* \wis{min}(\Z[x,x^{-1}])~:~\wis{abelian} \rightarrow \wis{sets} \qquad A \mapsto (\Z A)^*](/latexrender/pictures/348e71d9388433b1c044342490d78a05.gif)
of the integral group ring
usually is a lot bigger than
with the obvious (that is, extension of scalars) evaluation map 
with integral algebra
is a sub-functor of
(meaning that for every finite Abelian group
). As to the “best”-part, we must express that all other candidates factor through 
factors through an induced gadget-map
.
? Well, take any finitely generated integral algebra
to
means that there is a
such that for every finite Abelian group ![\xymatrix{A \ar[rr] \ar[d]_e & & Hom_{\Z-alg}(S, \Z A) \ar[d] \\
Hom_{\C-alg}(\C[x,x^{-1}],\C A) \ar[rr]^{- \circ \psi} & & Hom_{\C-alg}(S \otimes_{\Z} \C, \C A)} \xymatrix{A \ar[rr] \ar[d]_e & & Hom_{\Z-alg}(S, \Z A) \ar[d] \\
Hom_{\C-alg}(\C[x,x^{-1}],\C A) \ar[rr]^{- \circ \psi} & & Hom_{\C-alg}(S \otimes_{\Z} \C, \C A)}](/latexrender/pictures/22617cc650e703a4ebf10f890b4128f0.gif)
is the natural evaluation map defined before sending a group-element
to the algebra map defined by ![\xymatrix{S \ar[r]^{i} & S \otimes_{\Z} \C \ar[r]^{\psi} & \C[x,x^{-1}]} \xymatrix{S \ar[r]^{i} & S \otimes_{\Z} \C \ar[r]^{\psi} & \C[x,x^{-1}]}](/latexrender/pictures/58e32011ccc090a4a37645603ab13183.gif)
is a Laurent polynomial of degree say
with all coefficients a priori in
of order
, then the above commuting diagram applied to the generator of
(the evaluation of which is the natural projection map
) gives us the commuting diagram![\xymatrix{S \ar[r] \ar[d] & S \otimes_{\Z} \C \ar[r]^{\psi} & \C[x,x^{-1}] \ar[d]^{\pi} \\
\Z C_n = \frac{\Z[x,x^{-1}]}{(x^N-1)} \ar[rr]^j & & \frac{\C[x,x^{-1}]}{(x^N-1)}} \xymatrix{S \ar[r] \ar[d] & S \otimes_{\Z} \C \ar[r]^{\psi} & \C[x,x^{-1}] \ar[d]^{\pi} \\
\Z C_n = \frac{\Z[x,x^{-1}]}{(x^N-1)} \ar[rr]^j & & \frac{\C[x,x^{-1}]}{(x^N-1)}}](/latexrender/pictures/991b814484f04cef61d8fddb16f2e9ce.gif)
is the natural inclusion map. Tracing
along the diagram we see that indeed all coefficients of
have to be integers! Applying the same argument to the other generators of
and hence that
.
.
) has enough finite Abelian group-quotients. In other words,
… (to be continued when we’ll consider noncommutative
provided that the integral algebra
, whereas it is crucial in the Connes-Consani paper to consider more generally functors to graded sets. In the final part of this series we’ll explain what that’s all about.
I’ll try to give the essence of their definition of an affine scheme over
preserving the group-data. That is, f sends the unit element of A to that of B and
f sends a product of two elements in A to the product of their images in B. For example, if
is a cyclic group of order n with generator g and
is a cyclic group of order m with generator h, then every groupmorphism from A to B is entirely determined by the image of g let’s say that this image is
. But, as
and the conditions on a group-morphism we must have that
and therefore m must divide i.n. This gives you all possible group-morphisms from A to B.
between these two sacks? Well, F should map any abelian group A to a set F(A) and any group-morphism
and do all of this nicely. That is, F should send compositions of group-morphisms to compositions of the corresponding maps, and so on. If you take a pen and a piece of paper, you’re bound to come up with the exact definition of a functor (that’s what F is called).