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	<title>Comments on: smooth Brauer-Severis</title>
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		<title>By: hyper-resolutions &#124; neverendingbooks</title>
		<link>http://www.neverendingbooks.org/index.php/smooth-brauer-severis.html/comment-page-1#comment-4206</link>
		<dc:creator>hyper-resolutions &#124; neverendingbooks</dc:creator>
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		<description>&lt;p&gt;[...] Last time we saw that for $A$ a smooth order with center $R$ the Brauer-Severi variety $XA$ is a smooth variety and we have a projective morphism $XA rightarrow mathbf{max}~R$ This situation is very similar to that of a desingularization $~X rightarrow mathbf{max}~R$ of the (possibly singular) variety $~mathbf{max}~R$. The top variety $~X$ is a smooth variety and there is a Zariski open subset of $~mathbf{max}~R$ where the fibers of this map consist of just one point, or in more bombastic language a $~mathbb{P}^0$. The only difference in the case of the Brauer-Severi fibration is that we have a Zariski open subset of $~mathbf{max}~R$ (the Azumaya locus of A) where the fibers of the fibration are isomorphic to $~mathbb{P}^{n-1}$. In this way one might view the Brauer-Severi fibration of a smooth order as a non-commutative or hyper-desingularization of the central variety. This might provide a way to attack the old problem of construction desingularizations of quiver-quotients. If $~Q$ is a quiver and $alpha$ is an indivisible dimension vector (that is, the component dimensions are coprime) then it is well known (a result due to Alastair King) that for a generic stability structure $theta$ the moduli space $~M^{theta}(Q,alpha)$ classifying $theta$-semistable $alpha$-dimensional representations will be a smooth variety (as all $theta$-semistables are actually $theta$-stable) and the fibration $~M^{theta}(Q,alpha) rightarrow mathbf{iss}{alpha}~Q$ is a desingularization of the quotient-variety $~mathbf{iss}{alpha}~Q$ classifying isomorphism classes of $alpha$-dimensional semi-simple representations. However, if $alpha$ is not indivisible nobody has the faintest clue as to how to construct a natural desingularization of $~mathbf{iss}{alpha}~Q$. Still, we have a perfectly reasonable hyper-desingularization $~X{A(Q,alpha)} rightarrow mathbf{iss}{alpha}~Q$ where $~A(Q,alpha)$ is the corresponding quiver order, the generic fibers of which are all projective spaces in case $alpha$ is the dimension vector of a simple representation of $~Q$. I conjecture (meaning : I hope) that this Brauer-Severi fibration contains already a lot of information on a genuine desingularization of $~mathbf{iss}{alpha}~Q$. One obvious test for this seemingly crazy conjecture is to study the flat locus of the Brauer-Severi fibration. If it would contain info about desingularizations one would expect that the fibration can never be flat in a central singularity! In other words, we would like that the flat locus of the fibration is contained in the smooth central locus. This is indeed the case and is a more or less straightforward application of the proof (due to Geert Van de Weyer) of the Popov-conjecture for quiver-quotients (see for example his Ph.D. thesis Nullcones of quiver representations). However, it is in general not true that the flat-locus and central smooth locus coincide. Sometimes this is because the Brauer-Severi scheme is a blow-up of the Brauer-Severi of a nicer order. The following example was worked out together with Colin Ingalls : Consider the order $~A = begin{bmatrix} C[x,y] &amp; C[x,y] &#092; (x,y) &amp; C[x,y] end{bmatrix}$ which is the quiver order of the quiver setting $~(Q,alpha)$  then the Brauer-Severi fibration $~XA rightarrow mathbf{iss}{alpha}~Q$ is flat everywhere except over the zero representation where the fiber is $~mathbb{P}^1 times mathbb{P}^2$. On the other hand, for the order $~B = begin{bmatrix} C[x,y] &amp; C[x,y] &#092; C[x,y] &amp; C[x,y] end{bmatrix}$ the Brauer-Severi fibration is flat and $~XB simeq mathbb{A}^2 times mathbb{P}^1$. It turns out that $~XA$ is a blow-up of $~X_B$ at a point in the fiber over the zero-representation.   Sphere: Related Content [...]&lt;/p&gt;
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		<content:encoded><![CDATA[<p>[...] Last time we saw that for $A$ a smooth order with center $R$ the Brauer-Severi variety $XA$ is a smooth variety and we have a projective morphism $XA rightarrow mathbf{max}~R$ This situation is very similar to that of a desingularization $~X rightarrow mathbf{max}~R$ of the (possibly singular) variety $~mathbf{max}~R$. The top variety $~X$ is a smooth variety and there is a Zariski open subset of $~mathbf{max}~R$ where the fibers of this map consist of just one point, or in more bombastic language a $~mathbb{P}^0$. The only difference in the case of the Brauer-Severi fibration is that we have a Zariski open subset of $~mathbf{max}~R$ (the Azumaya locus of A) where the fibers of the fibration are isomorphic to $~mathbb{P}^{n-1}$. In this way one might view the Brauer-Severi fibration of a smooth order as a non-commutative or hyper-desingularization of the central variety. This might provide a way to attack the old problem of construction desingularizations of quiver-quotients. If $~Q$ is a quiver and $alpha$ is an indivisible dimension vector (that is, the component dimensions are coprime) then it is well known (a result due to Alastair King) that for a generic stability structure $theta$ the moduli space $~M^{theta}(Q,alpha)$ classifying $theta$-semistable $alpha$-dimensional representations will be a smooth variety (as all $theta$-semistables are actually $theta$-stable) and the fibration $~M^{theta}(Q,alpha) rightarrow mathbf{iss}{alpha}~Q$ is a desingularization of the quotient-variety $~mathbf{iss}{alpha}~Q$ classifying isomorphism classes of $alpha$-dimensional semi-simple representations. However, if $alpha$ is not indivisible nobody has the faintest clue as to how to construct a natural desingularization of $~mathbf{iss}{alpha}~Q$. Still, we have a perfectly reasonable hyper-desingularization $~X{A(Q,alpha)} rightarrow mathbf{iss}{alpha}~Q$ where $~A(Q,alpha)$ is the corresponding quiver order, the generic fibers of which are all projective spaces in case $alpha$ is the dimension vector of a simple representation of $~Q$. I conjecture (meaning : I hope) that this Brauer-Severi fibration contains already a lot of information on a genuine desingularization of $~mathbf{iss}{alpha}~Q$. One obvious test for this seemingly crazy conjecture is to study the flat locus of the Brauer-Severi fibration. If it would contain info about desingularizations one would expect that the fibration can never be flat in a central singularity! In other words, we would like that the flat locus of the fibration is contained in the smooth central locus. This is indeed the case and is a more or less straightforward application of the proof (due to Geert Van de Weyer) of the Popov-conjecture for quiver-quotients (see for example his Ph.D. thesis Nullcones of quiver representations). However, it is in general not true that the flat-locus and central smooth locus coincide. Sometimes this is because the Brauer-Severi scheme is a blow-up of the Brauer-Severi of a nicer order. The following example was worked out together with Colin Ingalls : Consider the order $~A = begin{bmatrix} C[x,y] &amp; C[x,y] &#92; (x,y) &amp; C[x,y] end{bmatrix}$ which is the quiver order of the quiver setting $~(Q,alpha)$  then the Brauer-Severi fibration $~XA rightarrow mathbf{iss}{alpha}~Q$ is flat everywhere except over the zero representation where the fiber is $~mathbb{P}^1 times mathbb{P}^2$. On the other hand, for the order $~B = begin{bmatrix} C[x,y] &amp; C[x,y] &#92; C[x,y] &amp; C[x,y] end{bmatrix}$ the Brauer-Severi fibration is flat and $~XB simeq mathbb{A}^2 times mathbb{P}^1$. It turns out that $~XA$ is a blow-up of $~X_B$ at a point in the fiber over the zero-representation.   Sphere: Related Content [...]</p>
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