http://www.neverendingbooks.org/index.php/monsieur-mathieu.html lieven le bruyn's blog Wed, 28 Jul 2010 16:42:15 +0200 hourly 1 http://wordpress.org/?v=3.0 http://www.neverendingbooks.org/index.php/monsieur-mathieu.html/comment-page-1#comment-8860 Anon Mon, 21 Jun 2010 04:23:15 +0000 http://www.neverendingbooks.org/?p=62#comment-8860 <p>For the sake of future readers, there's a typo in the second to last paragraph. In the sentence "with the vertices corresponding to the black vertices and the three points over 1 of multiplicity three corresponding to the trivalent vertices...", that 1 should be a 0. While I'm at it, there's an 8211 appearing mysteriously in one of the formulas above that.</p> For the sake of future readers, there’s a typo in the second to last paragraph. In the sentence “with the vertices corresponding to the black vertices and the three points over 1 of multiplicity three corresponding to the trivalent vertices…”, that 1 should be a 0. While I’m at it, there’s an 8211 appearing mysteriously in one of the formulas above that.

]]> http://www.neverendingbooks.org/index.php/monsieur-mathieu.html/comment-page-1#comment-5998 John McKay Sun, 14 Sep 2008 17:37:01 +0000 http://www.neverendingbooks.org/?p=62#comment-5998 <p>Mathieu's groups are attributed to the fact that 2x5+1=11, 2x11+1=23, primes. What can we say about thr statistics of lengths of sequences of primes of the form p[k+1] = 2p[k]+1 ? G.A.Miller, who enjoyed exhibiting the errors of others, wrote: On the supposed 5-fold transitive function of 24 elements and 19!/48 values. This in Messenger of Mathematics 1898 pp. 187-190, being 25 years after Mathieu's second paper! In 1900 in Bull. Math. Sci. France: Sur plusiers groupes simples (his sole paper en francais!) tells of his error. Frobenius used his character theory of the symmetric group to advantage when computing the Mathieu group characters. A remarkable achievement at that date. As for Galois groups, we find that Gal(x^24+x+t)/F2(t) = M24 as can (almost) be shown by hand.</p> Mathieu’s groups are attributed to the fact that 2×5+1=11, 2×11+1=23, primes. What can we say about thr statistics of lengths of sequences of primes of the form p[k+1] = 2p[k]+1 ? G.A.Miller, who enjoyed exhibiting the errors of others, wrote: On the supposed 5-fold transitive function of 24 elements and 19!/48 values. This in Messenger of Mathematics 1898 pp. 187-190, being 25 years after Mathieu’s second paper! In 1900 in Bull. Math. Sci. France: Sur plusiers groupes simples (his sole paper en francais!) tells of his error. Frobenius used his character theory of the symmetric group to advantage when computing the Mathieu group characters. A remarkable achievement at that date. As for Galois groups, we find that Gal(x^24+x+t)/F2(t) = M24 as can (almost) be shown by hand.

]]> http://www.neverendingbooks.org/index.php/monsieur-mathieu.html/comment-page-1#comment-3750 anabelian geometry | neverendingbooks Wed, 02 Jan 2008 19:15:20 +0000 http://www.neverendingbooks.org/?p=62#comment-3750 <p>[...] modular, geometry and groups Digg This [?] Table of contents for Dessins d'enfantsMonsieur MathieuThe best rejected proposal everThe cartographers’ groupsthe cartographers’ groups (2)the [...]</p> [...] modular, geometry and groups Digg This [?] Table of contents for Dessins d’enfantsMonsieur MathieuThe best rejected proposal everThe cartographers’ groupsthe cartographers’ groups (2)the [...]

]]> http://www.neverendingbooks.org/index.php/monsieur-mathieu.html/comment-page-1#comment-3631 The best rejected proposal ever at neverendingbooks Wed, 26 Dec 2007 14:46:11 +0000 http://www.neverendingbooks.org/?p=62#comment-3631 <p>[...] introduced his ‘Dessins d’enfants’ (Children’s drawings). Recall from last session the pictures of the left and right handed Monsieur [...]</p> [...] introduced his ‘Dessins d’enfants’ (Children’s drawings). Recall from last session the pictures of the left and right handed Monsieur [...]

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