lieven le bruyn's blog
Geometry of the Okubo algebra
Last week, Melanie Raczek gave a talk entitled ‘Cubic forms and Okubo product’ in our Artseminar, based on her paper On ternary cubic forms that determine central simple algebras of degree 3.
I had never heard of this strange non-associative product on 8-dimensional space, but I guess it is an instance of synchronicity that now the Okubo algebra seems to pop-up everywhere.
Yesterday, there was the post the Okubo algebra by John Baez at the n-cafe, telling that Susumu Okubo discovered his algebra while investigating quarks.
I don’t know a thing about the physics, but over the last days I’ve been trying to understand some of the miraculous geometry associated to the Okubo algebra. So, let’s start out by defining the ‘algebra’.
Consider the associative algebra of all 3×3 complex matrices
with the usual matrix-multiplication. In this algebra there is the 8-dimensional subspace of trace zero matrices, usually called the Lie algebra
. However, we will not use the Lie-bracket, only matrix-multiplication. Typical elements of
will be written as
and their entries will be denoted as

For any two elements
one defines their Okubo-product to be the 3×3 matrix

where
is a primitive 3-rd root of unity and
is the identity matrix. Written out in the entries of X and Y this operation looks horribly complicated

with

The crucial remark to make is that
is again a trace zero matrix. That is, we have defined a new operation on
.

This Okubo-product is neither a Lie-bracket, nor an associative multiplication. In fact, it is a lot ‘less associative’ than that other 8-dimensional algebra, the octonions. The only noteworthy identity it has is that
. So, why should we be interested in this horrible algebra?
Well, let us consider the subset of
consisting of those matrices X satusfying
. That is, with the above notation, all matrices X such that

In the 8-dimensional affine space
these matrices form a singular quadric with top the zero-matrix. So, it is better to go projective. That is, any non-zero matrix
determines a point in 7-dimensional projective space
with homogeneous coordinates
![\overline{X} = [x_0:x_1:x_2:x_3:x_4:x_5:x_6:x_7] \in \mathbb{P}^7 \overline{X} = [x_0:x_1:x_2:x_3:x_4:x_5:x_6:x_7] \in \mathbb{P}^7](/latexrender/pictures/abf863c11bda8eec6c894b039bac843c.gif)
and the points
corresponding to solutions of
form a smooth 6-dimensional quadric
with homogeneous equation

6-dimensional quadrics may be quite hard to visualize, so it may help to recall the classic situation of lines on a 2-dimensional quadric (animated gif taken from surfex).
A 2-dimensional quadric contains two families of lines, often called the ‘blue lines’ and the ‘red lines’, each of these lines isomorphic to
. The rules-of-intersection of these are :
- different red lines are disjoint as are different blue lines
- any red and any blue line intersect in exactly one point
- every point of the quadric lies on exactly one red and one blue line
The lines in either family are in one-to-one correspondence with the points on the projective line. We therefore say that there is a
-family of red lines and a
-family of blue lines on a 2-dimensional quadric.
A 6-dimensional quadric
contains two families of ’3-planes’. That is, there is a family of red
‘s contained in Q and a family of blue
‘s. Can we determine these red and blue 3-planes explicitly?
Yes we can, using the Okubo algebra-product on
. Take
defining the point
(that is,
). then all 3×3 matrices one obtains by taking the Okubo-product with left X-factor form a 4-dimensional linear subspace in 

so its non-zero matrices determine a 3-plane in
(consisting of all points with homogeneous coordinates
, using the above formulas) which actually lies entirely in the quadric Q. These are precisely the bLue 3-planes in Q. That is, the family of all bLue 3-planes consists precisely of the 3-planes
with
satisfying 
Phrased differently, any point
determines a blue 3-plane
.
Similarly, any point
determines a Red 3-plane by taking Okubo-products with Right X-factor, that is,
is a 3-plane for Q where

and all Red 3-planes for Q are of this form. But, this is not all… these correspondences are unique! That is, any point on the quadric defines a unique red and a unique blue 3-plane, or, phrased differently, there is a Q-family of red 3-planes and a Q-family of blue 3-planes in Q. This is a consequence of triality.
To see this, note that the automorphism group of a 6-dimensional smooth quadric is the rotation group
and this group has Dynkin diagram
, the most symmetrical of them all!
In general, every node in a Dynkin diagram has an interesting projective variety associated to it, a so called homogeneous space. I’ll just mention what these spaces are corresponding to the 4 nodes of
. Full details can be found in chapter 23 of Fulton and Harris’ Representation theory, a first course.
The left-most node corresponds to the orthogonal Grassmannian of isotropic 1-planes in
which is just a fancy way of viewing our quadric Q. The two right-most nodes correspond to the two connected components of the Grassmannians of isotropic 4-planes in
, which are our red resp. blue families of 3-planes on the quadric. Now, as the corresponding dotted Dynkin diagrams are isomorphic
there corresponding homogeneous spaces are also isomorphic. Thus indeed, there is a one-to-one correspondence between points of the quadric Q and red 3-planes on Q (and similarly with blue 3-planes on Q).
Okay, so the Okubo-product allows us to associate to a point on the 6-dimensional quadric Q a unique red 3-plane and a unique blue 3-plane (much as any point on a 2-dimensional quadric determines a unique red and blue line). Do these families of red and blue 3-planes also satisfy ‘rules-of-intersection’?
Yes they do and, once again, the Okubo-product clarifies them. Here they are :
- two different red 3-planes intersect in a unique line (as do different blue 3-planes)
- the bLue 3-plane
intersects the Red 3-plane
in a unique point if and only if the Okubo-product
- the bLue 3-plane
intersects the Red 3-plane
in a unique 2-plane if and only if the Okubo-product
That is, Right and Left Okubo-products determine the Red and bLue families of 3-planes on the 6-dimensional quadric as well as their intersections!
geometry| Print article | This entry was posted by lievenlb on March 14, 2009 at 5:10 pm, and is filed under geometry, groups. Follow any responses to this post through RSS 2.0. You can skip to the end and leave a response. Pinging is currently not allowed. |









about 1 year ago
This looks like Twistors. Is this Algebra related to them?
about 1 year ago
Thank you for this interesting and illuminating post (and for your kind words concerning my talk
.
about 1 year ago
Is anyone here familiar with the subset of 3×3 matrices that are “magic”, that is, where the sum of the three elements in a row or column does not depend on the row or column? These matrices are closed under addition and multiplication, include 0 and 1, and form a subgroup of the unitary matrices. They are related to the discrete Fourier transform on 3 vectors and 3 matrices, and on the permutation group on 3 elements. And they seem to have applications to the elementary particles.
The unitary magic matrices form a manifold with 4 real dimensions. I’ve linked in an elegant parameterization that is 4-dimensional and appears, by computer calculation, to parameterize the whole group but I can’t figure out how to prove it.