on June 15, 2008 by lieven in groups, Comments (4)
F_un and braid groups
Fun with F_un
- Looking for F_un
- The F_un folklore
- Absolute linear algebra
- F_un and braid groups
- F_un with Manin
Recall that an n-braid consists of n strictly descending elastic strings connecting n inputs at the top (named 1,2,…,n) to n outputs at the bottom (labeled 1,2,…,n) upto isotopy (meaning that we may pull and rearrange the strings in any way possible within 3-dimensional space). We can always change the braid slightly such that we can divide the interval between in- and output in a number of subintervals such that in each of those there is at most one crossing.
n-braids can be multiplied by putting them on top of each other and connecting the outputs of the first braid trivially to the inputs of the second. For example the 5-braid on the left can be written as
with
the braid on the top 3 subintervals and
the braid on the lower 5 subintervals.
In this way (and using our claim that there can be at most 1 crossing in each subinterval) we can write any n-braid as a word in the generators
(with
) being the overcrossing between inputs i and i+1. Observe that the undercrossing is then the inverse
. For example, the braid on the left corresponds to the word

Clearly there are relations among words in the generators. The easiest one we have already used implicitly namely that
is the trivial braid. Emil Artin proved in the 1930-ies that all such relations are consequences of two sets of ‘obvious’ relations. The first being commutation relations between crossings when the strings are far enough from each other. That is we have
whenever 
=
The second basic set of relations involves crossings using a common string

=
Starting with the 5-braid at the top, we can use these relations to reduce it to a simpler form. At each step we have outlined to region where the relations are applied
=
=
=
These beautiful braid-pictures were produced using the braid-metapost program written by Stijn Symens.
Tracing a string from an input to an output assigns to an n-braid a permutation on n letters. In the above example, the permutation is
. As this permutation doesn’t change under applying basic reduction, this gives a group-morphism

from the braid group on n strings
to the symmetric group. We have seen before that the symmetric group
has a F-un interpretation as the linear group
over the field with one element. Hence, we can ask whether there is also a F-un interpretation of the n-string braid group and of the above group-morphism.
Kapranov and Smirnov suggest in their paper that the n-string braid group
is the general linear group over the polynomial ring
over the field with one element and that the evaluation morphism (setting t=0)
gives the groupmorphism 
The rationale behind this analogy is a theorem of Drinfeld’s saying that over a finite field
, the profinite completion of
is embedded in the fundamental group of the space of q-polynomials of degree n in much the same way as the n-string braid group
is the fundamental group of the space of complex polynomials of degree n without multiple roots.
And, now that we know the basics of absolute linear algebra, we can give an absolute braid-group representation
![\mathbb{B}_n = GL_n(\mathbb{F}_1[t]) \rightarrow GL_n(\mathbb{F}_{1^n}) \mathbb{B}_n = GL_n(\mathbb{F}_1[t]) \rightarrow GL_n(\mathbb{F}_{1^n})](/latexrender/pictures/c9579ae63fe20dd91138d4f2ccf6c22f.gif)
obtained by sending each generator
to the matrix over
(remember that
where
are the n-th roots of unity)

and it is easy to see that these matrices do indeed satisfy Artin’s defining relations for
.








isar
June 19, 2008 @ 8:17 am
The “Fun with F_1″ article by Connes, Consani and Marcolli is available on the arXiv since last Saturday, as http://arxiv.org/abs/0806.2401
S CHEN
August 15, 2008 @ 9:10 pm
I am really interested in this topic.
Could someone send me by e-mail an electronic version of the (never-published) paper by Kapranov and Smirnov ?
My e-mail add is sch_hit@yahoo.com
Thanks!
S CHEN
August 17, 2008 @ 2:27 pm
I have found the link to the paper above from the second part of this series of blogs.
Thanks!
Per Vognsen
September 3, 2009 @ 4:13 pm
I should probably have read the rest of the series before posting comments on individual post; now the branched covering analogy that I described in my previous comment seems pretty clear and indisputable from looking at these braidings.
Thanks for a great series!